Integrand size = 23, antiderivative size = 281 \[ \int \frac {x^3 \left (a+b \log \left (c x^n\right )\right )^2}{(d+e x)^2} \, dx=\frac {4 a b d n x}{e^3}-\frac {4 b^2 d n^2 x}{e^3}+\frac {b^2 n^2 x^2}{4 e^2}+\frac {4 b^2 d n x \log \left (c x^n\right )}{e^3}-\frac {b n x^2 \left (a+b \log \left (c x^n\right )\right )}{2 e^2}-\frac {2 d x \left (a+b \log \left (c x^n\right )\right )^2}{e^3}+\frac {x^2 \left (a+b \log \left (c x^n\right )\right )^2}{2 e^2}-\frac {d^2 x \left (a+b \log \left (c x^n\right )\right )^2}{e^3 (d+e x)}+\frac {2 b d^2 n \left (a+b \log \left (c x^n\right )\right ) \log \left (1+\frac {e x}{d}\right )}{e^4}+\frac {3 d^2 \left (a+b \log \left (c x^n\right )\right )^2 \log \left (1+\frac {e x}{d}\right )}{e^4}+\frac {2 b^2 d^2 n^2 \operatorname {PolyLog}\left (2,-\frac {e x}{d}\right )}{e^4}+\frac {6 b d^2 n \left (a+b \log \left (c x^n\right )\right ) \operatorname {PolyLog}\left (2,-\frac {e x}{d}\right )}{e^4}-\frac {6 b^2 d^2 n^2 \operatorname {PolyLog}\left (3,-\frac {e x}{d}\right )}{e^4} \]
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Time = 0.20 (sec) , antiderivative size = 281, normalized size of antiderivative = 1.00, number of steps used = 13, number of rules used = 10, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.435, Rules used = {2395, 2333, 2332, 2342, 2341, 2355, 2354, 2438, 2421, 6724} \[ \int \frac {x^3 \left (a+b \log \left (c x^n\right )\right )^2}{(d+e x)^2} \, dx=\frac {6 b d^2 n \operatorname {PolyLog}\left (2,-\frac {e x}{d}\right ) \left (a+b \log \left (c x^n\right )\right )}{e^4}+\frac {2 b d^2 n \log \left (\frac {e x}{d}+1\right ) \left (a+b \log \left (c x^n\right )\right )}{e^4}+\frac {3 d^2 \log \left (\frac {e x}{d}+1\right ) \left (a+b \log \left (c x^n\right )\right )^2}{e^4}-\frac {d^2 x \left (a+b \log \left (c x^n\right )\right )^2}{e^3 (d+e x)}-\frac {2 d x \left (a+b \log \left (c x^n\right )\right )^2}{e^3}-\frac {b n x^2 \left (a+b \log \left (c x^n\right )\right )}{2 e^2}+\frac {x^2 \left (a+b \log \left (c x^n\right )\right )^2}{2 e^2}+\frac {4 a b d n x}{e^3}+\frac {4 b^2 d n x \log \left (c x^n\right )}{e^3}+\frac {2 b^2 d^2 n^2 \operatorname {PolyLog}\left (2,-\frac {e x}{d}\right )}{e^4}-\frac {6 b^2 d^2 n^2 \operatorname {PolyLog}\left (3,-\frac {e x}{d}\right )}{e^4}-\frac {4 b^2 d n^2 x}{e^3}+\frac {b^2 n^2 x^2}{4 e^2} \]
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Rule 2332
Rule 2333
Rule 2341
Rule 2342
Rule 2354
Rule 2355
Rule 2395
Rule 2421
Rule 2438
Rule 6724
Rubi steps \begin{align*} \text {integral}& = \int \left (-\frac {2 d \left (a+b \log \left (c x^n\right )\right )^2}{e^3}+\frac {x \left (a+b \log \left (c x^n\right )\right )^2}{e^2}-\frac {d^3 \left (a+b \log \left (c x^n\right )\right )^2}{e^3 (d+e x)^2}+\frac {3 d^2 \left (a+b \log \left (c x^n\right )\right )^2}{e^3 (d+e x)}\right ) \, dx \\ & = -\frac {(2 d) \int \left (a+b \log \left (c x^n\right )\right )^2 \, dx}{e^3}+\frac {\left (3 d^2\right ) \int \frac {\left (a+b \log \left (c x^n\right )\right )^2}{d+e x} \, dx}{e^3}-\frac {d^3 \int \frac {\left (a+b \log \left (c x^n\right )\right )^2}{(d+e x)^2} \, dx}{e^3}+\frac {\int x \left (a+b \log \left (c x^n\right )\right )^2 \, dx}{e^2} \\ & = -\frac {2 d x \left (a+b \log \left (c x^n\right )\right )^2}{e^3}+\frac {x^2 \left (a+b \log \left (c x^n\right )\right )^2}{2 e^2}-\frac {d^2 x \left (a+b \log \left (c x^n\right )\right )^2}{e^3 (d+e x)}+\frac {3 d^2 \left (a+b \log \left (c x^n\right )\right )^2 \log \left (1+\frac {e x}{d}\right )}{e^4}-\frac {\left (6 b d^2 n\right ) \int \frac {\left (a+b \log \left (c x^n\right )\right ) \log \left (1+\frac {e x}{d}\right )}{x} \, dx}{e^4}+\frac {(4 b d n) \int \left (a+b \log \left (c x^n\right )\right ) \, dx}{e^3}+\frac {\left (2 b d^2 n\right ) \int \frac {a+b \log \left (c x^n\right )}{d+e x} \, dx}{e^3}-\frac {(b n) \int x \left (a+b \log \left (c x^n\right )\right ) \, dx}{e^2} \\ & = \frac {4 a b d n x}{e^3}+\frac {b^2 n^2 x^2}{4 e^2}-\frac {b n x^2 \left (a+b \log \left (c x^n\right )\right )}{2 e^2}-\frac {2 d x \left (a+b \log \left (c x^n\right )\right )^2}{e^3}+\frac {x^2 \left (a+b \log \left (c x^n\right )\right )^2}{2 e^2}-\frac {d^2 x \left (a+b \log \left (c x^n\right )\right )^2}{e^3 (d+e x)}+\frac {2 b d^2 n \left (a+b \log \left (c x^n\right )\right ) \log \left (1+\frac {e x}{d}\right )}{e^4}+\frac {3 d^2 \left (a+b \log \left (c x^n\right )\right )^2 \log \left (1+\frac {e x}{d}\right )}{e^4}+\frac {6 b d^2 n \left (a+b \log \left (c x^n\right )\right ) \text {Li}_2\left (-\frac {e x}{d}\right )}{e^4}+\frac {\left (4 b^2 d n\right ) \int \log \left (c x^n\right ) \, dx}{e^3}-\frac {\left (2 b^2 d^2 n^2\right ) \int \frac {\log \left (1+\frac {e x}{d}\right )}{x} \, dx}{e^4}-\frac {\left (6 b^2 d^2 n^2\right ) \int \frac {\text {Li}_2\left (-\frac {e x}{d}\right )}{x} \, dx}{e^4} \\ & = \frac {4 a b d n x}{e^3}-\frac {4 b^2 d n^2 x}{e^3}+\frac {b^2 n^2 x^2}{4 e^2}+\frac {4 b^2 d n x \log \left (c x^n\right )}{e^3}-\frac {b n x^2 \left (a+b \log \left (c x^n\right )\right )}{2 e^2}-\frac {2 d x \left (a+b \log \left (c x^n\right )\right )^2}{e^3}+\frac {x^2 \left (a+b \log \left (c x^n\right )\right )^2}{2 e^2}-\frac {d^2 x \left (a+b \log \left (c x^n\right )\right )^2}{e^3 (d+e x)}+\frac {2 b d^2 n \left (a+b \log \left (c x^n\right )\right ) \log \left (1+\frac {e x}{d}\right )}{e^4}+\frac {3 d^2 \left (a+b \log \left (c x^n\right )\right )^2 \log \left (1+\frac {e x}{d}\right )}{e^4}+\frac {2 b^2 d^2 n^2 \text {Li}_2\left (-\frac {e x}{d}\right )}{e^4}+\frac {6 b d^2 n \left (a+b \log \left (c x^n\right )\right ) \text {Li}_2\left (-\frac {e x}{d}\right )}{e^4}-\frac {6 b^2 d^2 n^2 \text {Li}_3\left (-\frac {e x}{d}\right )}{e^4} \\ \end{align*}
Time = 0.14 (sec) , antiderivative size = 240, normalized size of antiderivative = 0.85 \[ \int \frac {x^3 \left (a+b \log \left (c x^n\right )\right )^2}{(d+e x)^2} \, dx=\frac {-8 d e x \left (a+b \log \left (c x^n\right )\right )^2+2 e^2 x^2 \left (a+b \log \left (c x^n\right )\right )^2+\frac {4 d^3 \left (a+b \log \left (c x^n\right )\right )^2}{d+e x}+16 b d e n x \left (a-b n+b \log \left (c x^n\right )\right )+b e^2 n x^2 \left (b n-2 \left (a+b \log \left (c x^n\right )\right )\right )+12 d^2 \left (a+b \log \left (c x^n\right )\right )^2 \log \left (1+\frac {e x}{d}\right )+4 d^2 \left (-\left (\left (a+b \log \left (c x^n\right )\right ) \left (a+b \log \left (c x^n\right )-2 b n \log \left (1+\frac {e x}{d}\right )\right )\right )+2 b^2 n^2 \operatorname {PolyLog}\left (2,-\frac {e x}{d}\right )\right )+24 b d^2 n \left (\left (a+b \log \left (c x^n\right )\right ) \operatorname {PolyLog}\left (2,-\frac {e x}{d}\right )-b n \operatorname {PolyLog}\left (3,-\frac {e x}{d}\right )\right )}{4 e^4} \]
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Result contains higher order function than in optimal. Order 9 vs. order 4.
Time = 0.55 (sec) , antiderivative size = 824, normalized size of antiderivative = 2.93
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\[ \int \frac {x^3 \left (a+b \log \left (c x^n\right )\right )^2}{(d+e x)^2} \, dx=\int { \frac {{\left (b \log \left (c x^{n}\right ) + a\right )}^{2} x^{3}}{{\left (e x + d\right )}^{2}} \,d x } \]
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\[ \int \frac {x^3 \left (a+b \log \left (c x^n\right )\right )^2}{(d+e x)^2} \, dx=\int \frac {x^{3} \left (a + b \log {\left (c x^{n} \right )}\right )^{2}}{\left (d + e x\right )^{2}}\, dx \]
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\[ \int \frac {x^3 \left (a+b \log \left (c x^n\right )\right )^2}{(d+e x)^2} \, dx=\int { \frac {{\left (b \log \left (c x^{n}\right ) + a\right )}^{2} x^{3}}{{\left (e x + d\right )}^{2}} \,d x } \]
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\[ \int \frac {x^3 \left (a+b \log \left (c x^n\right )\right )^2}{(d+e x)^2} \, dx=\int { \frac {{\left (b \log \left (c x^{n}\right ) + a\right )}^{2} x^{3}}{{\left (e x + d\right )}^{2}} \,d x } \]
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Timed out. \[ \int \frac {x^3 \left (a+b \log \left (c x^n\right )\right )^2}{(d+e x)^2} \, dx=\int \frac {x^3\,{\left (a+b\,\ln \left (c\,x^n\right )\right )}^2}{{\left (d+e\,x\right )}^2} \,d x \]
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